The work done in lifting a 30 kg set of bricks to a height of 20m is We all know the FORMULA IN FINDING WORK is W = F x D Where W is work; F is force; and D is distance However, let us first discuss what work really is. When there is an object being moved by a force through a certain distance, the measure of energy transfer is what we call WORK . One of the most common units used in work is JOULES (commonly used as a unit of energy). It is the work by which 1 Newton (1N = 1 kg.m/sec^2) of force is used/expended through a distance of 1 meter (1m). Refer to the problem. It is said that the 30 kg set of bricks are to be raised in a height of 20 meters. As we see, there is no force given. But recall that force (F) is the product of mass (m) of an object and its acceleration (a) F = ma However, in the formula, (g = 9.81 m/s^2) or acceleration due to gravity is used in replacement of (a) because the object is moving upward. So now we have F = mg Thus, we have the new ...
What is the mass of an object that requires a force of 30 N to accelerate at a rate of 5m/sec² Given: F = 30N(Newton), A = 5m/sec², M = ? M=F/A = 30N/5m/sec² = 6kg ( convert the N to kg & m/sec², cancel the m/sec² and whats left is the kg, so kg is the unit of 6. So, 6kg is the mass of the object.
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